-[7z-(17z+3)]=3+(9z+0)

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Solution for -[7z-(17z+3)]=3+(9z+0) equation:


Simplifying
-1[7z + -1(17z + 3)] = 3 + (9z + 0)

Reorder the terms:
-1[7z + -1(3 + 17z)] = 3 + (9z + 0)
-1[7z + (3 * -1 + 17z * -1)] = 3 + (9z + 0)
-1[7z + (-3 + -17z)] = 3 + (9z + 0)

Reorder the terms:
-1[-3 + 7z + -17z] = 3 + (9z + 0)

Combine like terms: 7z + -17z = -10z
-1[-3 + -10z] = 3 + (9z + 0)
[-3 * -1 + -10z * -1] = 3 + (9z + 0)
[3 + 10z] = 3 + (9z + 0)

Reorder the terms:
3 + 10z = 3 + (0 + 9z)
Remove the zero:
3 + 10z = 3 + (9z)
3 + 10z = 3 + (9z)

Add '-3' to each side of the equation.
3 + -3 + 10z = 3 + -3 + (9z)

Combine like terms: 3 + -3 = 0
0 + 10z = 3 + -3 + (9z)
10z = 3 + -3 + (9z)

Combine like terms: 3 + -3 = 0
10z = 0 + (9z)
10z = (9z)

Solving
10z = (9z)

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '(-9z)' to each side of the equation.
10z + (-9z) = (9z) + (-9z)

Combine like terms: 10z + (-9z) = 1z
1z = (9z) + (-9z)

Combine like terms: (9z) + (-9z) = 0
1z = 0

Divide each side by '1'.
z = 0

Simplifying
z = 0

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